Order and degree of the differential equation `[1+(dy/dx)^3]^(7/3)=7(d^2y)/(dx^2)` are respectively

(A) 2, 3

(B) 3, 2

(C) 7, 2

(D) 3, 7

The order and degree of the differential equation `[1+(dy/dx)^3]^(7/3)=7(d^2y)/(dx^2)` are respectively

(A) 2, 3

(B) 3, 2

(C) 2, 2

(D) 3, 3

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#### Solution

`[1+(dy/dx)^3]^(7/3)=7(d^2y)/(dx^2)`

Cubing on both sides, we get

`[1+(dy/dx)^3]^(7)=7((d^2y)/(dx^2))^3`

By definition of degree and order Degree: 3 ; Order: 2

Concept: Order and Degree of a Differential Equation

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